Optimal. Leaf size=229 \[ -\frac{b \text{PolyLog}\left (2,-\frac{\left (e-\sqrt{e^2-c^2 d^2}\right ) e^{-\text{sech}^{-1}(c x)}}{c d}\right )}{e}-\frac{b \text{PolyLog}\left (2,-\frac{\left (\sqrt{e^2-c^2 d^2}+e\right ) e^{-\text{sech}^{-1}(c x)}}{c d}\right )}{e}+\frac{b \text{PolyLog}\left (2,-e^{-2 \text{sech}^{-1}(c x)}\right )}{2 e}+\frac{\left (a+b \text{sech}^{-1}(c x)\right ) \log \left (\frac{\left (e-\sqrt{e^2-c^2 d^2}\right ) e^{-\text{sech}^{-1}(c x)}}{c d}+1\right )}{e}+\frac{\left (a+b \text{sech}^{-1}(c x)\right ) \log \left (\frac{\left (\sqrt{e^2-c^2 d^2}+e\right ) e^{-\text{sech}^{-1}(c x)}}{c d}+1\right )}{e}-\frac{\log \left (e^{-2 \text{sech}^{-1}(c x)}+1\right ) \left (a+b \text{sech}^{-1}(c x)\right )}{e} \]
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Rubi [A] time = 0.933496, antiderivative size = 229, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 2, integrand size = 16, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.125, Rules used = {6287, 2518} \[ -\frac{b \text{PolyLog}\left (2,-\frac{\left (e-\sqrt{e^2-c^2 d^2}\right ) e^{-\text{sech}^{-1}(c x)}}{c d}\right )}{e}-\frac{b \text{PolyLog}\left (2,-\frac{\left (\sqrt{e^2-c^2 d^2}+e\right ) e^{-\text{sech}^{-1}(c x)}}{c d}\right )}{e}+\frac{b \text{PolyLog}\left (2,-e^{-2 \text{sech}^{-1}(c x)}\right )}{2 e}+\frac{\left (a+b \text{sech}^{-1}(c x)\right ) \log \left (\frac{\left (e-\sqrt{e^2-c^2 d^2}\right ) e^{-\text{sech}^{-1}(c x)}}{c d}+1\right )}{e}+\frac{\left (a+b \text{sech}^{-1}(c x)\right ) \log \left (\frac{\left (\sqrt{e^2-c^2 d^2}+e\right ) e^{-\text{sech}^{-1}(c x)}}{c d}+1\right )}{e}-\frac{\log \left (e^{-2 \text{sech}^{-1}(c x)}+1\right ) \left (a+b \text{sech}^{-1}(c x)\right )}{e} \]
Antiderivative was successfully verified.
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Rule 6287
Rule 2518
Rubi steps
\begin{align*} \int \frac{a+b \text{sech}^{-1}(c x)}{d+e x} \, dx &=-\frac{\left (a+b \text{sech}^{-1}(c x)\right ) \log \left (1+e^{-2 \text{sech}^{-1}(c x)}\right )}{e}+\frac{\left (a+b \text{sech}^{-1}(c x)\right ) \log \left (1+\frac{\left (e-\sqrt{-c^2 d^2+e^2}\right ) e^{-\text{sech}^{-1}(c x)}}{c d}\right )}{e}+\frac{\left (a+b \text{sech}^{-1}(c x)\right ) \log \left (1+\frac{\left (e+\sqrt{-c^2 d^2+e^2}\right ) e^{-\text{sech}^{-1}(c x)}}{c d}\right )}{e}-\frac{b \int \frac{\sqrt{\frac{1-c x}{1+c x}} \log \left (1+e^{-2 \text{sech}^{-1}(c x)}\right )}{x (1-c x)} \, dx}{e}+\frac{b \int \frac{\sqrt{\frac{1-c x}{1+c x}} \log \left (1+\frac{\left (e-\sqrt{-c^2 d^2+e^2}\right ) e^{-\text{sech}^{-1}(c x)}}{c d}\right )}{x (1-c x)} \, dx}{e}+\frac{b \int \frac{\sqrt{\frac{1-c x}{1+c x}} \log \left (1+\frac{\left (e+\sqrt{-c^2 d^2+e^2}\right ) e^{-\text{sech}^{-1}(c x)}}{c d}\right )}{x (1-c x)} \, dx}{e}\\ &=-\frac{\left (a+b \text{sech}^{-1}(c x)\right ) \log \left (1+e^{-2 \text{sech}^{-1}(c x)}\right )}{e}+\frac{\left (a+b \text{sech}^{-1}(c x)\right ) \log \left (1+\frac{\left (e-\sqrt{-c^2 d^2+e^2}\right ) e^{-\text{sech}^{-1}(c x)}}{c d}\right )}{e}+\frac{\left (a+b \text{sech}^{-1}(c x)\right ) \log \left (1+\frac{\left (e+\sqrt{-c^2 d^2+e^2}\right ) e^{-\text{sech}^{-1}(c x)}}{c d}\right )}{e}+\frac{b \text{Li}_2\left (-e^{-2 \text{sech}^{-1}(c x)}\right )}{2 e}-\frac{b \text{Li}_2\left (-\frac{\left (e-\sqrt{-c^2 d^2+e^2}\right ) e^{-\text{sech}^{-1}(c x)}}{c d}\right )}{e}-\frac{b \text{Li}_2\left (-\frac{\left (e+\sqrt{-c^2 d^2+e^2}\right ) e^{-\text{sech}^{-1}(c x)}}{c d}\right )}{e}\\ \end{align*}
Mathematica [C] time = 0.522587, size = 393, normalized size = 1.72 \[ \frac{a \log (d+e x)}{e}+\frac{b \left (\text{PolyLog}\left (2,-e^{-2 \text{sech}^{-1}(c x)}\right )-2 \left (\text{PolyLog}\left (2,\frac{\left (\sqrt{e^2-c^2 d^2}-e\right ) e^{-\text{sech}^{-1}(c x)}}{c d}\right )+\text{PolyLog}\left (2,-\frac{\left (\sqrt{e^2-c^2 d^2}+e\right ) e^{-\text{sech}^{-1}(c x)}}{c d}\right )-\text{sech}^{-1}(c x) \log \left (\frac{\left (e-\sqrt{e^2-c^2 d^2}\right ) e^{-\text{sech}^{-1}(c x)}}{c d}+1\right )-\text{sech}^{-1}(c x) \log \left (\frac{\left (\sqrt{e^2-c^2 d^2}+e\right ) e^{-\text{sech}^{-1}(c x)}}{c d}+1\right )+2 i \sin ^{-1}\left (\frac{\sqrt{\frac{e}{c d}+1}}{\sqrt{2}}\right ) \log \left (\frac{\left (e-\sqrt{e^2-c^2 d^2}\right ) e^{-\text{sech}^{-1}(c x)}}{c d}+1\right )-2 i \sin ^{-1}\left (\frac{\sqrt{\frac{e}{c d}+1}}{\sqrt{2}}\right ) \log \left (\frac{\left (\sqrt{e^2-c^2 d^2}+e\right ) e^{-\text{sech}^{-1}(c x)}}{c d}+1\right )-4 i \sin ^{-1}\left (\frac{\sqrt{\frac{e}{c d}+1}}{\sqrt{2}}\right ) \tanh ^{-1}\left (\frac{(e-c d) \tanh \left (\frac{1}{2} \text{sech}^{-1}(c x)\right )}{\sqrt{e^2-c^2 d^2}}\right )+\text{sech}^{-1}(c x) \log \left (e^{-2 \text{sech}^{-1}(c x)}+1\right )\right )\right )}{2 e} \]
Warning: Unable to verify antiderivative.
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Maple [C] time = 0.271, size = 514, normalized size = 2.2 \begin{align*}{\frac{a\ln \left ( cxe+cd \right ) }{e}}+{\frac{b{\rm arcsech} \left (cx\right )}{e}\ln \left ({ \left ( -cd \left ({\frac{1}{cx}}+\sqrt{-1+{\frac{1}{cx}}}\sqrt{1+{\frac{1}{cx}}} \right ) +\sqrt{-{c}^{2}{d}^{2}+{e}^{2}}-e \right ) \left ( -e+\sqrt{-{c}^{2}{d}^{2}+{e}^{2}} \right ) ^{-1}} \right ) }+{\frac{b{\rm arcsech} \left (cx\right )}{e}\ln \left ({ \left ( cd \left ({\frac{1}{cx}}+\sqrt{-1+{\frac{1}{cx}}}\sqrt{1+{\frac{1}{cx}}} \right ) +\sqrt{-{c}^{2}{d}^{2}+{e}^{2}}+e \right ) \left ( e+\sqrt{-{c}^{2}{d}^{2}+{e}^{2}} \right ) ^{-1}} \right ) }+{\frac{b}{e}{\it dilog} \left ({ \left ( cd \left ({\frac{1}{cx}}+\sqrt{-1+{\frac{1}{cx}}}\sqrt{1+{\frac{1}{cx}}} \right ) +\sqrt{-{c}^{2}{d}^{2}+{e}^{2}}+e \right ) \left ( e+\sqrt{-{c}^{2}{d}^{2}+{e}^{2}} \right ) ^{-1}} \right ) }+{\frac{b}{e}{\it dilog} \left ({ \left ( -cd \left ({\frac{1}{cx}}+\sqrt{-1+{\frac{1}{cx}}}\sqrt{1+{\frac{1}{cx}}} \right ) +\sqrt{-{c}^{2}{d}^{2}+{e}^{2}}-e \right ) \left ( -e+\sqrt{-{c}^{2}{d}^{2}+{e}^{2}} \right ) ^{-1}} \right ) }-{\frac{b{\rm arcsech} \left (cx\right )}{e}\ln \left ( 1+i \left ({\frac{1}{cx}}+\sqrt{-1+{\frac{1}{cx}}}\sqrt{1+{\frac{1}{cx}}} \right ) \right ) }-{\frac{b{\rm arcsech} \left (cx\right )}{e}\ln \left ( 1-i \left ({\frac{1}{cx}}+\sqrt{-1+{\frac{1}{cx}}}\sqrt{1+{\frac{1}{cx}}} \right ) \right ) }-{\frac{b}{e}{\it dilog} \left ( 1+i \left ({\frac{1}{cx}}+\sqrt{-1+{\frac{1}{cx}}}\sqrt{1+{\frac{1}{cx}}} \right ) \right ) }-{\frac{b}{e}{\it dilog} \left ( 1-i \left ({\frac{1}{cx}}+\sqrt{-1+{\frac{1}{cx}}}\sqrt{1+{\frac{1}{cx}}} \right ) \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} b \int \frac{\log \left (\sqrt{\frac{1}{c x} + 1} \sqrt{\frac{1}{c x} - 1} + \frac{1}{c x}\right )}{e x + d}\,{d x} + \frac{a \log \left (e x + d\right )}{e} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{b \operatorname{arsech}\left (c x\right ) + a}{e x + d}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{a + b \operatorname{asech}{\left (c x \right )}}{d + e x}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{b \operatorname{arsech}\left (c x\right ) + a}{e x + d}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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